Post by wasting on Mar 23, 2004 14:52:03 GMT -5
im a c newbee complete at awe with pointers
code1
br]char *p;
char a[]="patrik";
p=a;
while (*p!='\0')
{printf("%c",*p);
p++;}
code2br] char *p;
char a[]="patrik";
p=a;
while (*p!='\0')
{printf("%c",*p);
*p++;}
both the codes give the same o/p inspite of me incrementing the ptr add val in the first case where as i increase the val of the data to which the prt is pointing.
how is this possible??
code1
br]char *p;char a[]="patrik";
p=a;
while (*p!='\0')
{printf("%c",*p);
p++;}
code2
br] char *p;char a[]="patrik";
p=a;
while (*p!='\0')
{printf("%c",*p);
*p++;}
both the codes give the same o/p inspite of me incrementing the ptr add val in the first case where as i increase the val of the data to which the prt is pointing.
how is this possible??