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Post by Ohio on Jun 23, 2003 9:44:19 GMT -5
John, Matt, and Richard can build a garage in 6 days. If Matt and Richard work together, they can build the garage in 9 days. If John and Richard work together, they can build the garage in 8 days.
How many days would each man take to build the garage if they worked alone?
This one should take a bit longer
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Tewl
xTeam
C# & VB Developer
Posts: 495
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Post by Tewl on Jun 23, 2003 11:13:05 GMT -5
I'm at work I'll look over it again when i get home, but heres a guess
John 9 days
Matt 10 days
Richard 11 days
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Post by Ohio on Jun 23, 2003 11:18:26 GMT -5
Try again Tewl, good guess though.
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Post by tek on Jun 23, 2003 11:22:24 GMT -5
John is a common name  |
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Post by w0rd on Jun 23, 2003 13:50:09 GMT -5
Lmao @ tek's educated answer  |
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Post by w0rd on Jun 23, 2003 13:57:12 GMT -5
Ok, I've probably done this all wrong but here goes.. John = a Matt = b Richard = c SOa + b + c = 6 [Divide by 3 = 2 days each] b + c = 9 [Divide by 2 = 4.5 days each] a + c = 8 [Divide by 2 = 4 days each] SOIf we add the individual days up we get.. a = 6 days (John) b = 6.5 days (Matt) c = 10.5 days (Richard) Thats wrong isnt it  lol.. just a guess. |
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Post by Cypher on Jun 23, 2003 14:24:02 GMT -5
when they work together they arent going to work at the same speed , right  |
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z00ey
New Member
return is the movement of sense..
Posts: 2,309
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Post by z00ey on Jun 23, 2003 14:53:46 GMT -5
just saw it and have no solution yet, but right, cypher.. ..would make no sense else because the qestion itself would be false then..
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Post by tek on Jun 23, 2003 15:47:26 GMT -5
What if John dies 3 days into it then Matt dies 2 days later then how long will it take to build?...huh...HUH?!
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Post by Cypher on Jun 23, 2003 15:58:21 GMT -5
you work the builders too hard tek.  |
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Post by Cypher on Jun 23, 2003 17:30:20 GMT -5
John : 18 days Matt : 24 days Richard : 14.4 days (14 days 6 hours) it all works out right through my checking but didnt expect a decimal place. lol. and they look too high J + M + R = 1/6 m + r = 1/9 j + r = 1/8 j + 1/9 = 1/6 j = 1/18 therefore john does it in 18 days j + r = 1/8 1/18 + r = 1/8 r = 5/72 therefore richard does it in 14.4 days m + 5/72 = 1/9 m = 1/24 therefore matt takes 24 days 1/6 - 1/18 - 5/72 - 1/24 = 0 |
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Post by Ohio on Jun 23, 2003 20:28:25 GMT -5
Perfect Cypher, Well done.
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Post by Cypher on Jun 24, 2003 1:20:17 GMT -5
;D i used speed=distance/time stuff .  so its like speed=garages/time tek if your dying question is about the John, Matt, and Richard group then 1/18 * 3 + 1/24 * 5 = 0.375 1 - 0.375 = 0.625 0.625 / 5/72 = 9.000058 it would take John, Matt, and Richard 9 days if John dies 3 days into it then Matt dies 2 days later. ;D |
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z00ey
New Member
return is the movement of sense..
Posts: 2,309
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Post by z00ey on Jun 24, 2003 11:24:11 GMT -5
..could have mentioned that "J" means John works one day and "1/6" means (1/6)garage, in case ppl don t understand what you did, lol..
..nahh, no bothering, i slept away over it yesterday, so *pats cypher*
..and LOL ! (if john dies...) ;D
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Post by Cypher on Jun 24, 2003 11:34:21 GMT -5
nah. j is johns building speed in garage per days. the time it takes to build a garage is the number of garages (1) divided by the speed of johns building . J == g/d (garage per days) john makes 1 garage every 18 days if that explains it any better. |
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lol.. just a guess.
so its like speed=garages/time