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Post by anastas on May 5, 2004 16:10:23 GMT -5
I was recently bored in math class and I decided to play around with Fermat's Last Theorem. Here's what I got (with i = sqr(-1) and -x^n means the opposite of the nth power of x, NOT the nth power of -x) br] 1. Assume there are solutions to x^n + y^n = z^n br]x^n + y^n = z^n 2. Factor as the sum of two exponents br](x^.5n + i*y^.5n)(x^.5n - i*y^.5n) = z^n 3. Factor out i br]i[(i * -x^.5n + y^.5n)(i * -x^.5n - y^.5n)] = z^n 4. Simplify inner terms br]i(-x^n - y^n) = z^n 5. Divide both sides by i br]-x^n - y^n = (z^n)/i 6. Rationalize the denomantor of the right-hand term br]-x^n - y^n = i*-z^n 7. Multiply both sides by -1 br]x^n + y^n = i*z^n 8. Statement 7 contradicts Statement 1 as z^n does not equal i*z^n (other that z=0 of course) so the original statements must be false. Therefore, there are no solutions to x^n + y^n = z^n. Now I know that prooving this theorem can't be that simple and I have no reason to suppose I can do it since I'm only 15 and in Algebra 2 (although I have gone through calc and stat textbooks). I can't find any mistakes, anyone care to proove my proof wrong? I just really want to know where my mistake(s) is/are.
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Post by infamous1 on May 28, 2004 18:54:17 GMT -5
I could be wrong, but here is what I saw.
In step 3, you factor i from both parts being multiplied, so you need to square i.
3. (i^2)[(i * -x^.5n + y^.5n)(i * -x^.5n - y^.5n)] = z^n should be the correct step.
Tell me if this makes more sense.
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Post by anastas on May 29, 2004 12:04:45 GMT -5
I don't think so as I am not factoring i out from both expressions in parentheses separately, I am facting i out of the entire expression at once. This can be checked by distributing i to each of the bracketed terms, which results in the equation in step 2.
Thanks for the reply though.
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Post by .•´¯`•þasђγ•._.•´ on May 29, 2004 12:17:43 GMT -5
ummmmm, yeah...what he said....
lol
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Post by infamous1 on May 29, 2004 12:29:13 GMT -5
2. (x^.5n + i*y^.5n)(x^.5n - i*y^.5n) = z^n
3. i(i * -x^.5n + y^.5n) i(i * -x^.5n - y^.5n) = z^n
4. (i^2)[(i * -x^.5n + y^.5n)(i * -x^.5n - y^.5n)] = z^n
If (x^.5n + i*y^.5n) = i(i * -x^.5n + y^.5n) and (x^.5n - i*y^.5n) = i(i * -x^.5n - y^.5n) then you must square I. One of these two assumptions may be where I went wrong. Tell me if they are not correct.
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Post by anastas on May 29, 2004 20:26:34 GMT -5
Well, yes, but there's one difference br] If (x^.5n + i*y^.5n) = i(i * -x^.5n + y^.5n) and (x^.5n - i*y^.5n) = i(i * -x^.5n - y^.5n) then (x^.5n + i*y^.5n)(x^.5n - i*y^.5n) = i(i * -x^.5n + y^.5n) * i(i * -x^.5n - y^.5n) and i(i * -x^.5n + y^.5n) * i(i * -x^.5n - y^.5n) = i[(i * -x^.5n + y^.5n) * (i * -x^.5n - y^.5n)]. This can be checked by then simplifying the last expression by reversing the previous steps, resulting in the original equation. I could be wrong, but I'm pretty sure it's correct. I think I figured out what's wrong with it - I assumed the equation's domain including the maginar numbers but since no domain is explicity stated, it is assumed to be the real numbers. I am working outside its domain so that's why it's incorrect. Thank you for the feedback, however.
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Post by infamous1 on May 29, 2004 21:17:12 GMT -5
OK, just so you found where it was wrong
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